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September 16, 2014

September 16, 2014

Posted by **Bryan** on Friday, March 19, 2010 at 4:42pm.

cos(4/5 - 5/13)

Is this what I would do?

- math -
**drwls**, Friday, March 19, 2010 at 4:48pmYour sin(x) fraction lacks a numerator

- math -
**Bryan**, Friday, March 19, 2010 at 4:51pmthe sine is 4/5 sorry!

- math -
**drwls**, Friday, March 19, 2010 at 8:13pmNo, that is not what you would do. Call the angles A and B.

For the angles you have chosen,

cos(x) = 3/5 and sin(y) = 12/13. You can prove that with the Pythagorean theorem, or sin^2 + cos^2 = 1. That will make the calculation easier.

Then use the identity:

cos(A-B) = cosA cosB + sinA sin B

= (3/5)(5/13) + (4/5)(12/13)

= (15 + 48)/65 = 63/65

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