Posted by **Pacifico** on Friday, March 19, 2010 at 3:53pm.

If we know that the length of time it takes a college student to find a parking spot in the library parking lot follows a normal distribution with a mean of 3.5 minutes and a standard deviation of 1 minute, find the point in the distribution in which 75.8% of the college students exceed when trying to find a parking spot in the library parking lot.

A. 2.8 minutes

B. 3.2 minutes

C. 3.4 minutes

D. 4.2 minutes

- Statistics -
**bobpursley**, Friday, March 19, 2010 at 4:38pm
http://davidmlane.com/hyperstat/z_table.html

- Statistics -
**PsyDAG**, Saturday, March 20, 2010 at 12:20pm
Without that site, you can still figure it out.

Z = (x - mean)/standard deviation

In the back of your text, there is a table labeled something like "areas under normal distribution." Find that percentage in the table to determine your Z score. Put the values in the above equation and solve.

I hope this helps a little more.

- Statistics -
**Pacifico**, Monday, March 22, 2010 at 4:12pm
Thank you for your help bobpursley and PsyDAG.

I believe the answer is 2.8 minutes. However, the wording of the question using 'exceed' is confusing to me. How do you confirm it is indeed 2.8 minutes and not 4.2 minutes.

Thanks again.

- Statistics -
**Anonymous**, Monday, October 31, 2016 at 9:25am
If we know carry equal marks library parking lot time it takes college student to nnd a parking spot in the deviation of follows a normal distribution with a mean of 3.5 minut a parking 1 minute, find the probability that a r randomly selected college student will find a spot in the library parking lot in less than 3 minutes

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