Posted by john 2020 on Thursday, March 18, 2010 at 11:16pm.
use the given info. to find the exact value of the trig function.
csc u=-6/5, tan u is greater than 0
Find cos u/2
precal - Reiny, Thursday, March 18, 2010 at 11:58pm
csc u = -6/5
sinu = -5/6
by Pythagoras, and knowing sin u is negative and tan u is positive
cosu = -√11/6
we know cosA = 1 - 2cos^2(A/2)
cosu = 1 - 2cos^2(u/2)
-√11/6 = 1 - 2cos^2(u/2)
2cos^2(u/2) = 1 + √11/6)
cos u/2 = √[(1 + √11/6)/2]
check my arithmetic,
precal - john 2020, Friday, March 19, 2010 at 12:03am
can u simplify the answer any more?????
Correction - precal - Reiny, Friday, March 19, 2010 at 12:15am
I had the formula backwards, ...
Should have been
cos A = 2cos^2(A/2) - 1
cos u = 2cos^2 (u/2) - 1
-√11/6 + 1 = 2cos^2 (u/2)
-√[1 - √11/6)/2] = cos (u/2)
I picked the negative value, since we knew u was in III, so u/2 was in II, and in II the cosine is negative.
Since you wanted the "exact" value, there is no point simplifying the above answer.
precal - john 2020, Friday, March 19, 2010 at 12:17am
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