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April 20, 2014

April 20, 2014

Posted by **Katie** on Thursday, March 18, 2010 at 9:04pm.

A(s)<->1/2B(g)+C(g) k1=0.0334

3D(g)<->B(g)+2C(g) k2=2.35

I know that you have to make modifications according to the stoichiometric coeffecients. So do I divide k1 by 2 and the multiply that by the inverse of 2.35 (which = 1/2.35 because the equation is reversed)?

I got this answer, is this correct?

0.0034/2=0.0167*(1/2.35)

=0.0071

is this correct?

- Chemistry -
**DrBob222**, Thursday, March 18, 2010 at 9:28pmIf I understand what you did, I disagree with the answer. Dividing k1 by 2 means you have the reacton 1/2 A --> 1/4 B and that won't add up to anything.

I think what you want to do is to multiply equation 1 by 2 to give you

2A ==>B + 2C

Then reverse equation 2 to give

2C + B ==> 3D

--------------------

Then add those two equations to obtain

2A ==> 3D which is what the problem asked for.

So you want to square k1 and reverse k2, then multiply those.

Check me out on that.

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