I am stumped!!! quadratic equation

solve for x:
xsq+16x+4=0

please show the steps

What method?

x^2 + 16x + 4 = 0
I would use completing the square ...
x^2 + 16x + 64 = -4 + 64
(x+8)^2 = 60
x+8 = ± √60
x = -8 ± 2√15

Using the formula will of course yield the same answer after some simplification.

What's the answer I need it asap! 49y2-64

To solve the quadratic equation x^2 + 16x + 4 = 0, you can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

The equation is in the form ax^2 + bx + c = 0, where a = 1, b = 16, and c = 4.

Step 1: Identify the values of a, b, and c in the equation.
- In this case, a = 1, b = 16, and c = 4.

Step 2: Substitute the values of a, b, and c into the quadratic formula.
- x = (-16 ± √(16^2 - 4(1)(4))) / (2(1))

Step 3: Simplify the expression inside the square root.
- x = (-16 ± √(256 - 16)) / 2

Step 4: Evaluate the expression inside the square root.
- x = (-16 ± √240) / 2

Step 5: Simplify the square root.
- x = (-16 ± √(16 * 15)) / 2
- x = (-16 ± 4√15) / 2

Step 6: Simplify the expression by factoring out 2.
- x = (-8 ± 2√15)

Therefore, the equation x^2 + 16x + 4 = 0 has two solutions:
- x = (-8 + 2√15)
- x = (-8 - 2√15)