what is the electron arrangement for boron? and how do you find the valence electron for it? i know it has 3 v.e. but how do you find it
The electron arrangement for boron can be determined by using the periodic table and the principles of electron configuration. Boron has an atomic number of 5, meaning it has five electrons.
To determine the electron arrangement, you can start by filling the 1s orbital, which can hold a maximum of 2 electrons. Then, move on to the 2s orbital, which can also hold a maximum of 2 electrons. After that, fill the 2p orbital, which can hold a maximum of 6 electrons. However, in the case of boron, only 3 of the 6 possible positions in the 2p orbital are occupied.
So the electron arrangement for boron is: 1s² 2s² 2p¹
Now, to find the valence electrons, you need to look at the outermost energy level. In the case of boron, the outermost energy level is the second shell (2s² 2p¹). The 2s² part of the electron arrangement is considered the core electrons, while the 2p¹ part represents the valence electrons. Since there is only 1 electron in the 2p orbital, boron has 1 valence electron.
In general, to find the valence electrons for an element, you can identify the outermost energy level and count the number of electrons in that level. These electrons are typically involved in chemical bonding and determining the element's reactivity.