Posted by James on Wednesday, March 17, 2010 at 7:55pm.
There is not enough information here.
Suppose an electron is released from rest in a uniform electric field whose magnitude is 4.70 103 N/C.
(a)How much work is done by the field in moving the electron through a distance of 7 cm?
J
(b) Through what potential difference will it have passed after moving through this distance?
V
(c) How fast will the electron be moving after it has traveled this distance?
m/s
E = 4.7*10^3 N/C
Force = Q E = 1.6*10^-19 * 4.7*10^3
work = force * distance = Force*.07 meters
potential difference = E*distance
(1/2) m v^2 = charge * potential difference, m = 9.1*10^-31 kg
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