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March 27, 2015

March 27, 2015

Posted by **Abbey** on Wednesday, March 17, 2010 at 12:18am.

sin[x + pi/4] + sin[x-pi/4] = -1

sinx cospi/4 + cosxsin pi/4 + sinx cos pi/4 - cosx sin pi/4 = -1

2 sin x cos pi/4 =-1

cos pi/4 = sqr2/2

2sin^x(sqrt2/2) = -1

sin x = -sqrt2

x = 7pi/4 and 5pi/4

Am I correct?

- Math(Please help) -
**Damon**, Wednesday, March 17, 2010 at 6:51am2sin^x(sqrt2/2) = -1

sin x = -1/sqrt2 = - sqrt 2 /2

x = pi + pi/4 = 5 pi/4

x = 2 pi - pi/4 = 7 pi /4

so I agree with you but you seem to have a typo

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