A sample of silver at 20.0 °C is heated to 100 °C when 1000 cal is added. What is the mass of the silver? (csilver = 0.056 cal/deg-gm)

The temperature change is 80 C.

That is called "delta T"

Use this formula:

Q = M*C*(delta T)
Q is the added heat energy.

M = Q/[C*(delta T)]
= 1000 Cal/[0.056 Cal/g C*80 C]
= ___ gm

Well, you've got a hot silver situation on your hands! Let's see if we can solve it using some clown-calculus.

First, let's find the temperature difference by subtracting the initial temperature from the final temperature: 100°C - 20.0°C = 80.0°C

Next, let's use the formula for heat (Q = mcΔT) to find the mass of the silver. We have all the other values, so we can rearrange the formula to solve for mass (m).

Given that the amount of heat (Q) is 1000 cal and the specific heat (c) is 0.056 cal/deg-gm, we can plug in the values:

1000 cal = (mass) * (0.056 cal/deg-gm) * (80.0°C)

Now we just need to solve for the mass, so let's divide both sides of the equation by (0.056 cal/deg-gm) * (80.0°C):

mass = 1000 cal / ((0.056 cal/deg-gm) * (80.0°C))

Now, if my clown calculations are correct, you should have the mass of the silver!

To find the mass of the silver, we can use the formula for heat:

Q = mcΔT

Where:
Q = heat added (in calories)
m = mass of silver (in grams)
c = specific heat capacity of silver (in cal/deg-gm)
ΔT = change in temperature (in °C)

We are given:
Q = 1000 cal
ΔT = 100 °C - 20 °C = 80 °C
c = 0.056 cal/deg-gm

Let's substitute the values into the formula and solve for the mass:

1000 cal = m * 0.056 cal/deg-gm * 80 °C

Dividing both sides of the equation by 0.056 cal/deg-gm * 80 °C:

1000 cal / (0.056 cal/deg-gm * 80 °C) = m

m = 1785.71 gm

Therefore, the mass of the silver is approximately 1785.71 grams.

To find the mass of the silver, we can use the formula for heat (q) as follows:

q = m * c * ΔT

where:
q is the heat absorbed (in calories)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in cal/deg-gm)
ΔT is the change in temperature (in degrees Celsius)

In this case, we are given:
q = 1000 cal
ΔT = 100 °C - 20 °C = 80 °C
c = 0.056 cal/deg-gm

Plugging in these values into the formula, we can solve for the mass (m):

1000 cal = m * 0.056 cal/deg-gm * 80 °C

To solve the equation, we'll first cancel out the units: calories and degrees Celsius.

1000 cal = m * 0.056 * 80

Next, we'll simplify the right side of the equation:

1000 = m * 4.48

Now, we can isolate the variable m:

m = 1000 / 4.48

Using a calculator, we find:

m ≈ 223.21 grams

Therefore, the mass of the silver is approximately 223.21 grams.