How much heat must be removed from 500 g of water at 0 °C to form ice at 0 °C?
q = mass water x heat fusion.
q will be in the same units as heat fusion.
To find out how much heat must be removed from 500 g of water at 0 °C to form ice at 0 °C, we need to calculate the heat required for the phase change from liquid to solid.
The heat required for changing the state of a substance is given by the equation:
Q = m × L
where Q is the heat, m is the mass, and L is the latent heat of fusion. The latent heat of fusion for water is approximately 334 Joules per gram.
First, let's calculate the heat required to change the state of 500 g of water at 0 °C:
Q = 500 g × 334 J/g
Q = 167,000 J
Therefore, 167,000 Joules of heat must be removed from 500 g of water at 0 °C to form ice at 0 °C.