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Posted by on Tuesday, March 16, 2010 at 8:01pm.

I need to write 4x^2 - y^2 -8x -4y + 16 = 0 in standard form and I keep getting it wrong. Could someone please help me. Thanks

  • math 30 - , Tuesday, March 16, 2010 at 8:26pm

    4(x^2-2x+1) -(y^2 +4y+4)=-16

    (x-1)^2/1- (y+2)^2/2^2=-1

    Now this negative sign presents a problem, so

    (y+2)^2/4^2 -(x-1)^2/2=1

    check that.

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