Posted by L** on Tuesday, March 16, 2010 at 7:29pm.
For the first one,
Absorbance = kc
A = 0.585, solve for k, c =- 2.50 x 10^-6M
Use k in the second run of the concd stuff.
A = kc
You will get a concn that must be adjusted because of the dilution. How much was it diluted. From 5 to 150 mL; therefore, the concn will whatever you calculate x the factor 150/5.
Or you can look at it another way. You can say that the absorbance would have been higher than 0.289 by 0.289 x (150/5), then work A = kc the normal way.
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