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March 1, 2015

March 1, 2015

Posted by **Anonymous** on Tuesday, March 16, 2010 at 3:48pm.

m^-1+z^-1

_________

m^-1- z^-1

- Algebra -
**Reiny**, Tuesday, March 16, 2010 at 4:23pm= (1/m + 1/z)/(1/m - 1/z)

= [(z+m)/(mz)]/[(z-m)/zm]

= (z+m)/(z-m)

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