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March 29, 2015

March 29, 2015

Posted by **Matt** on Tuesday, March 16, 2010 at 3:22pm.

- Math -
**Reiny**, Tuesday, March 16, 2010 at 4:30pmRS

= 1/cos2x + sin2x/cos2x

= 1/(cos^2x - sin^2x) + 2sinxcosx/cos^2x - sin^2x)

= (1 + 2sinxcosx)/[(cosx+sinx)(cosx-sinx)]

= (sin^2x + 2sinxcosx + cos^2x)/[(cosx+sinx)(cosx-sinx)]

= (sinx + cosx)^2/[(cosx+sinx)(cosx-sinx)]

= (sinx + cosx)/(cosx - sinx)

= LS

- Math -
**Matt**, Tuesday, March 16, 2010 at 11:08pmThank you very much!

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