Posted by Lisa on Monday, March 15, 2010 at 11:01pm.
3000+ 400n where n = # of year
n=1 (first year) 3000+400n = 3000 +400(1) = 3400
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n= 15 (15th year) 3000+ 400(15) = 3000+ 6000 = 9000
maybe this is rite?
Thanks, I think this is correct. I n elp w/ the concepts.
during 1st year = 3000
during 2nd year = 3000 + 1(400)
during 3rd year = 3000 + 2(400)
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during 15th year = 3000 + 14(400) = 8600
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