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April 18, 2014

April 18, 2014

Posted by **RAMATU** on Monday, March 15, 2010 at 7:37pm.

- PRE CAL. JOURNAL -
**MathMate**, Monday, March 15, 2010 at 9:41pmYou can calculate the different combinations to get different colours, but you can also calculate the probability P of getting the same colours, and the required probability is 1-P.

get two reds: (3/6)*(2/5)=1/5

get two blues: (2/6)*(1/6)=1/18

Probability of getting two reds or two blues: (1/5)+(1/18)=23/90

Probability of not getting two of the same colour = 1-(23/90)=67/90

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