Posted by Alyssa Pacheco on Sunday, March 14, 2010 at 10:56pm.
(3x^11z^5)^3 = 27 x^33 z^15
b) and c) are not clear since you don't use proper brackets
3a) again, your lack of brackets make it ambiguous
I will assume you mean
x^2/5 + (x-5)/6 = 0
x^2/5 = (5-x)/6
6x^2 = 25 - 5x
6x^2 + 5x - 25 = 0
your answer is correct
18 = 2(3)^(x+3)
9 = 3^(x+3)
3^2 = 3^(x+2)
so x+2 = 2
x = 0
128 = 4^(3x)
2^7 = (2^2)^(3x)
2^7 = 2^(6x)
6x = 7
x = 7/6
this is how 2b and 2c is written:
Does that help?
that is what think alyssa is trying to say?
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