posted by anonymous on .
There is 0.150 moles of H2 and I2, and are brought to equilibrium in a 3.30 L flask. The equation is H2 + I2 = 2HI. Find the equilibrium amounts of H2, I2, and HI.
I'm not getting the correct answer. I set up the formula as x^2/(.04545-x) (.04545-x). To get moles I multiplied the resulting molar concentration by the 3.30 liters. what am i doing something wrong
and KC = 50.2
If you are letting x stand for the amount of H2 and I2 that combine, then HI = 2x; otherwise what you have looks ok to me.
so the equation would be 2x/(.04545-x)(.04545-x)?
i mean 2x^2?
I would use 2x^2. yes.