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March 26, 2017

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There is 0.150 moles of H2 and I2, and are brought to equilibrium in a 3.30 L flask. The equation is H2 + I2 = 2HI. Find the equilibrium amounts of H2, I2, and HI.

I'm not getting the correct answer. I set up the formula as x^2/(.04545-x) (.04545-x). To get moles I multiplied the resulting molar concentration by the 3.30 liters. what am i doing something wrong

  • chemistry - ,

    and KC = 50.2

  • chemistry - ,

    If you are letting x stand for the amount of H2 and I2 that combine, then HI = 2x; otherwise what you have looks ok to me.

  • chemistry - ,

    so the equation would be 2x/(.04545-x)(.04545-x)?

  • chemistry - ,

    i mean 2x^2?

  • chemistry - ,

    I would use 2x^2. yes.

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