Aqueous solution with a pH of 10.6 is diluted from 1 L to 1.5 L. What is the pH of the diluted solution?

I assume this is a strong acid.

Convert pH to (H^+)
mL x M = mL x M
Then convert M back to pH.

To determine the pH of the diluted solution, it is important to understand how dilution affects pH. When an acidic or basic solution is diluted, the concentration of hydrogen ions (H+) or hydroxide ions (OH-) changes relative to the volume of the solution. pH measures the concentration of H+ ions in a solution and is calculated using the equation pH = -log[H+].

In this case, the initial aqueous solution has a pH of 10.6 and is diluted from 1 L to 1.5 L. To find the pH of the diluted solution, we can use the concept of dilution.

Dilution is a process in which the concentration of a solution is reduced by adding additional solvent (in this case, water). It is important to note that the number of moles of solute remains constant before and after dilution.

Using the dilution equation, which states that the initial concentration multiplied by the initial volume equals the final concentration multiplied by the final volume, we can calculate the new concentration of the solution after dilution:

Initial concentration × initial volume = final concentration × final volume

Let's assume the initial concentration of H+ ions in the solution is [H+]1 and the final concentration is [H+]2, the initial volume is 1 L, and the final volume is 1.5 L.

[H+]1 × 1 L = [H+]2 × 1.5 L

Since the moles of solute remain constant, we know that the volume ratio is the same as the molar concentration ratio. Therefore, we can write:

[H+]1/[H+]2 = 1.5 L/1 L

Simplifying this equation gives us:

[H+]2 = [H+]1 × (1 L/1.5 L)

Now, we can substitute the pH value of the initial solution into the equation. Since pH = -log[H+], we can rewrite the equation as:

[H+]2 = 10^(-pH1) × (1 L/1.5 L)

Calculating this equation will give us the final concentration of H+ ions in the diluted solution. To find the corresponding pH, we'll use the equation pH = -log[H+].

So, by substituting the values into the equation, we can calculate the pH of the diluted solution.