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March 6, 2015

March 6, 2015

Posted by **Selma** on Saturday, March 13, 2010 at 11:19pm.

- Physics -
**drwls**, Sunday, March 14, 2010 at 8:27amCompare the resistance of the annular pipe with that of the water column of the same length.

Riron = (r,iron)L/[pi(ro^2 - ri^2]

Rwater = (r,water)L/[pi*ri^2]

You will need to look up the resisitivity of iron pipe. It is about 10^-7 Ohm-meters, which is 10^-5 times that of water.

The area ratio

(ro^2 - ri^2/ri^2 = (ro/ri)^^2 -1 = 0.56

R,iron/R,water = 10^-5/0.56, so water will conduct only about 2* 10^-5 of the current

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