# pre-calculus

posted by
**hawra** on
.

the function has a real zero in the given interval. approximate this solution correct to two decimal places: f(x)=x^4-x^3-7x^2+5x+10; (2,3)

posted by
**hawra** on
.

the function has a real zero in the given interval. approximate this solution correct to two decimal places: f(x)=x^4-x^3-7x^2+5x+10; (2,3)