Posted by hawra on Saturday, March 13, 2010 at 8:35pm.
the function has a real zero in the given interval. approximate this solution correct to two decimal places: f(x)=x^4x^37x^2+5x+10; (2,3)

precalculus  Damon, Saturday, March 13, 2010 at 9:06pm
y =x^4x^37x^2+5x+10
y' = 4x^3 3x^2 14x +5
start with x1 = 2.5
calculate y there call it y1
calculate y' there, call it m
next guess at x2 = x1  y/m

precalculus  hawra, Saturday, March 13, 2010 at 9:19pm
thank you for your time and work. i really appreciate it. god bless you.
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