math
posted by Kristin .
1)
x+8y=33
x+4y=3
I need help solving this one using the elimination method!

x+8y=33  (1)
x+4y=3  (2)
(1) + (2),
x + 8y + (x + 4y) = 33 + 3
12y = 36
y = 3
sub y = 3 into (2),
x + 4(3) = 3
x = 3  12
x = 9
x = 9
CHECK: sub x = 9 and y = 3 into (1),
9 + 8(3) = 33