2H2 + O2 yield 2H2O , so if i switch it around, 2H2O yield 2H2 + O2. Would it change which one is breaking bond, which one is making bond. So technically is the left side always breaking bond, right side is forming bond
yes that is true. think of decomposition of KCLO3 to give kcl and o2
Isn't that the way we write equations to show REACTANTS on the left and PRODUCTS on the right. So we usually are talking breaking bonds on the left and making bonds on the right.
Yes, you are correct. In a chemical reaction, the reactants (on the left side of the equation) are always breaking bonds and the products (on the right side of the equation) are forming bonds.
In the reaction you provided, 2H2 + O2 yield 2H2O, the reactants are 2 molecules of hydrogen gas (H2) and 1 molecule of oxygen gas (O2). These reactants are breaking the bonds within the molecules to form the products, which are 2 molecules of water (H2O).
Now, if you switch the reaction around, it becomes 2H2O yield 2H2 + O2. The reactant now is 2 molecules of water, and the products are 2 molecules of hydrogen gas and 1 molecule of oxygen gas. In this case, the bonds within the water molecules are being broken, and new bonds are forming to produce the hydrogen and oxygen gas.
So, whether it is the left side or the right side of the chemical equation, the reactants are always breaking bonds, and the products are always forming bonds.