Posted by **Anonymous** on Saturday, March 13, 2010 at 12:47am.

Calculate the free energy (ΔG˚) of reaction (kJ) for the equation as written at 298 K (Dependence of temperature on enthalpy can be disregard). If the answer is negative, enter the sign and then the magnitude. Express your answer to three significant figures.

CaO(s) + H2O(l) → Ca(OH)2(s)

I know this part (Hess's Law stuff):

FYI the numbers were given enthalpy values.

DeltaG=DeltaH-TDeltaS

DeltaH=-986.1-[-635.1-285.83]=-65.17

DeltaS=83.4-[39.7+69.91]=-26.17

Then you plug it in the equation and solve for DeltaG, but when they say to disregard the temperature, does that mean I don't plug in the 298 to T or do I?

- Chemistry -
**DrBob222**, Saturday, March 13, 2010 at 1:12am
If the delta G" is delta G^{o}, I think you are supposed to look up the value of delta G^{o} in a set of tables. DG^{o} for the rxn = [DG^{o} products] -[DG^{o} reactants]

- Chemistry -
**Anonymous**, Saturday, March 13, 2010 at 1:15am
Hmmm...well the problem gives us a table of values for DeltaH and DeltaS for the compounds, but purposely left the DeltaG for the compounds blank, so I'm assuming they want you to use what values they give you to solve for it.

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