Posted by Abril on Saturday, March 13, 2010 at 12:44am.
First determine the moles chloride ion.
moles = M x L = 0.12L x 0.12 M NaCl = xx moles
moles = M x L = 0.22 L x 0.19 M MgCl2 = yy moles MgCl2. Multiply that by 2 since there are 2 moles Cl in each mole MgCl2 to obtain the moles chloride in that solution. yy moles x 2 = zz moles.
Total moles chloride = xx + zz = total.
What volume of 0.22 M AgNO3 will ppt the total moles. M = moles/ L. You know moles and you know M, calculate Liters.
.445 L
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