Thursday

October 30, 2014

October 30, 2014

Posted by **Chris** on Saturday, March 13, 2010 at 12:14am.

- Math -
**Reiny**, Saturday, March 13, 2010 at 7:56amLet the function be y = x^(1/3)

so we know (125, 5) lies on it, we need (123, ?)

dy/dx = (1/3)x^(-2/3)

at (125,5) , dy/dx = 1/75

the tangent equation is y = (1/75)x + b

but (125,5) is on it

5 = (1/75)(125) + b

5 = 5/3 + b

b = 10/3

tangent line at (125,5) is y = (1/75)x + 10/3

so when x = 123

y = 123/75 + 10/3 = 4.9733

(calculator answer for 123^(1/3) is 4.97319

**Answer this Question**

**Related Questions**

math - Use linear approximation, i.e. the tangent line, to approximate ((125.1...

Calculus (Tangent Line Approximation) - Use tangent line approximation to derive...

Calculus - Use linear approximation, i.e. the tangent line, to approximate (the ...

ap calculus ab - for f(x)=lnx we know that f(e)=1. Use the tangent line at(e,1) ...

Derivatives? - Given that f(-0.5)=2 and f'(-0.5)=4, use a tangent line ...

Math - Use linear approximation, i.e. the tangent line, to approximate 1.6^3 as ...

Calculus - Use linear approximation, i.e. the tangent line, to approximate 8.4^(...

Calculus - Use linear approximation, i.e. the tangent line, to approximate 8.4...

Tangent Line Approximation - Given that f(−0.5) = 2 f(−0.5) = 4 , ...

Math - Use linear approximation, i.e. the tangent line, to approximate sqrt[3...