Posted by **jake** on Friday, March 12, 2010 at 10:09am.

Short projectile motion question

A German rocket from the second world war had a range of 3000meters reaching a maximum height of 1000meters.

Determine the rockets maximum velocity

- physics -
**Vipin**, Friday, March 12, 2010 at 11:00am
Contact me

- physics -
**tchrwill**, Saturday, March 13, 2010 at 2:24pm
Vertical height h = V^2(sin^µ)/2g.

Horizontal distance = d = V^2(sin2µ)/g.

h = height, meters V = initial launch velocity, m/s, g = acceleration due to gravity, m/s^2s and µ = the elevation angle of the rocket measured from the horizontal to the launch directiion.

Thus, h = V^2(sin^2µ)/2g = 1000 and

......d = V^2(sin2µ)/g = 3000.

Solve for V^2, equate the results and solve for µ and then V.

Ignoring atmospheric drag and the influence of gravity.

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