In the circuit below all light bulbs are identical.
In order of brightest to dimmest the light bulbs are ...
This is the best I could do, to try and replicate what the original circuit looks like : where the x's are just the wire; A,B, C, D, and E are the lightbulbs; and the = is the battery/capacitor.. (Note: all the ~ were just to fill up the empty spaces, otherwise my diagram would go wacko, hope this works!)
xxxxxxxxxxx
x~~~~x~~~~x
x~~~~x~~~~x
+~~~~A~~~~D
=~~~~x~~~~x
-~~~~x~~~~x
x~~xxxxx~~E
x~~x~~~x~~x
x~~x~~~x~~x
x~~B~~~C~~x
x~~x~~~x~~x
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The choices are as follows:
1) D = E > A > B = C
2) A > D > E > B > C
3) D = E > B = C > A
4) A > D > E > B = C
5) A > D = E > B = C
To determine the order of brightness for the light bulbs in the circuit, you can consider the fact that light bulbs in parallel have the same brightness, while light bulbs in series share the voltage and therefore may have different brightnesses.
Starting from the battery/capacitor (=), follow the wires to determine the series and parallel connections between the light bulbs.
Let's start with the parallel connection. In the middle row, light bulbs B and C are connected in parallel, as they share the same wire connections on both sides. Therefore, B and C have the same brightness.
Next, moving to the bottom row, light bulbs D and E are connected in series. Series connection means that the current passes through one component after another. In this case, since D and E are in series, they will share the voltage. Thus, D and E have the same brightness.
Now, in the top row, we have light bulbs A, D, and E connected in parallel. Since D and E have the same brightness, we can conclude that A also has the same brightness as D and E.
Combining the above information, we can determine the order of brightness for the light bulbs:
D = E = A, B = C
Therefore, the correct order of brightness for the light bulbs is:
1) D = E = A
2) B = C