Posted by **Arielt** on Thursday, March 11, 2010 at 4:38pm.

Number of possible turning points in the following equation

f(x)=x^2(x-3)(x+4)

show work please

- Precalculus(URGENT) -
**drwls**, Thursday, March 11, 2010 at 4:40pm
Sorry, I only do the non-URGENT ones

- Precalculus(URGENT) -
**bobpursley**, Thursday, March 11, 2010 at 4:40pm
look at the factors. THere is a turning point at 3, -4. At zero, f(x) keeps the same curvature.

- Precalculus(URGENT) -
**Arielt**, Thursday, March 11, 2010 at 5:05pm
so does that mean there are 2 turning points

- Precalculus(URGENT) -
**Arielt**, Thursday, March 11, 2010 at 5:28pm
Number of possible turning points in the following equation

f(x)=x^2(x-3)(x+4)

are there 2 turning points or three turning points on the graph

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