Posted by Arielt on Thursday, March 11, 2010 at 4:38pm.
Number of possible turning points in the following equation
f(x)=x^2(x3)(x+4)
show work please

Precalculus(URGENT)  drwls, Thursday, March 11, 2010 at 4:40pm
Sorry, I only do the nonURGENT ones

Precalculus(URGENT)  bobpursley, Thursday, March 11, 2010 at 4:40pm
look at the factors. THere is a turning point at 3, 4. At zero, f(x) keeps the same curvature.

Precalculus(URGENT)  Arielt, Thursday, March 11, 2010 at 5:05pm
so does that mean there are 2 turning points

Precalculus(URGENT)  Arielt, Thursday, March 11, 2010 at 5:28pm
Number of possible turning points in the following equation
f(x)=x^2(x3)(x+4)
are there 2 turning points or three turning points on the graph