Post a New Question


posted by .

Two balls, of masses = .029 kg and = .06 kg, are suspended. The lighter ball is pulled away to a 60 degree angle with the vertical and released. What is the speed of the lighter ball before impact?

  • physics -

    How high did it go? YOu have to calculate its initial Potential Energy, mgh.

  • physics -

    Since they are talking about "before impact", you only need to equate the initial potential energy of the pulled-awy ball and equate it to the kinetic energy before impact. This will lead to
    V = sqrt(2gh)

    Are there other parts to the question that ask what happens AFTER impact? If not, I don't see why they are providing data on the second ball.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question