Posted by Anonymous on .
Two balls, of masses = .029 kg and = .06 kg, are suspended. The lighter ball is pulled away to a 60 degree angle with the vertical and released. What is the speed of the lighter ball before impact?
How high did it go? YOu have to calculate its initial Potential Energy, mgh.
Since they are talking about "before impact", you only need to equate the initial potential energy of the pulled-awy ball and equate it to the kinetic energy before impact. This will lead to
V = sqrt(2gh)
Are there other parts to the question that ask what happens AFTER impact? If not, I don't see why they are providing data on the second ball.