Posted by Anonymous on Thursday, March 11, 2010 at 10:33am.
a)centripetal acceleration is v^2/r. In this case, v is 30 mi/hr and r = 200 ft. The inertial force would be:
F = ma = mv^2/r (1)
This would be the friction force required to keep the car on its path. b) The static friction is:
F = uN (2)
where u is the static friction coefficient and N is the normal force (in this case the weight of the car). Setting (1) equal to (2)
mv^2/r = uN (3a)
m = N (3b)
combine (3a) and (3b) and solve for u.
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