Math
posted by Liz on .
Write an equation of the line containing the given point and parellel to the given line.
(2,6); 9x5y=4

rearranging the given line,
y = (9/5)x  4/5 (1)
which has the form
y = mx + b (2)
where m is the slope and b is the y intercept.
The new line would have the same slope to be parallel, so it would have the form:
y = (9/5)x + b (3)
to solve for b, input the given coordinates, obtaining:
(6) = (9/5)(2) + b
rearrange and solve for b, then substitute back into equation (3) 
It looks like b = 30/5 18/5 = 48/5
So
y = (9/5)x  48/5
(or 9x5y=48)
Check: when x = 2,
y = 18/5  48/5 = 30/5 = 6
Looks OK 
The new equation must be something like
9x  5y = c
plug in the given point(2,6)
18 + 30 = c = 48
all done : 9x  5y = 48