Posted by **Liz** on Thursday, March 11, 2010 at 1:20am.

Write an equation of the line containing the given point and parellel to the given line.

(2,-6); 9x-5y=4

- Math -
**FredR**, Thursday, March 11, 2010 at 1:58am
rearranging the given line,

y = (9/5)x - 4/5 (1)

which has the form

y = mx + b (2)

where m is the slope and b is the y intercept.

The new line would have the same slope to be parallel, so it would have the form:

y = (9/5)x + b (3)

to solve for b, input the given coordinates, obtaining:

(-6) = (9/5)(2) + b

rearrange and solve for b, then substitute back into equation (3)

- Math -
**drwls**, Thursday, March 11, 2010 at 6:55am
It looks like b = -30/5 -18/5 = -48/5

So

y = (9/5)x - 48/5

(or 9x-5y=48)

Check: when x = 2,

y = 18/5 - 48/5 = -30/5 = -6

Looks OK

- Math -
**Reiny**, Thursday, March 11, 2010 at 8:05am
The new equation must be something like

9x - 5y = c

plug in the given point(2,-6)

18 + 30 = c = 48

all done : 9x - 5y = 48

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