Posted by Sammy on Wednesday, March 10, 2010 at 11:21pm.
If the volume increases, the pressure must decrease AND the concn must decrease (moles/greater volume = smaller concn).
If Kc = (NH3)(HCl). Then making (NH3) and (HCl) smaller means the product becomes less than Kc and the reaction must shift to increase it to the original value of Kc. The only way it can do that is to shift the equilibrium to the right. That's the long approach. The shorter approach is to say (for a gas reaction) that increasing P will shift the equilibrium to the side with the smaller number of moles. So increase P and we see a shift to left. Decrease P and it goes to the right. Same answer but shorter.
For b), changing the pressure has no effect BECAUSE the moles of gas is the same on both sides. But you can get the same answer if we want to go the concn route. Kc = (NO)^2/(N2)(O2)
If we increase the volume, then concn is moles/larger V = smaller number.
(moles NO/V)(moles NO/V)/(moles N2/V)(moles O2/V) and you notice V cancels so it makes no difference what we choose for a volume (or pressure).
Related Questions
chem - The decomposition of ammonium hydrogen sulfide that is shown below is an ...
Science- Chemistry Ap - 2SO3(g) -> 2SO2(g) + O2(g) Delta H = 197kj For ...
Chemistry - Sulfur trioxide gas, one of the causes of acid rain, is produced in ...
chem - Ammonium carbonate (solid) decomposes when heated to produce three ...
college chem - Ammonium carbonate (solid) decomposes when heated to produce ...
math - Hi! Can anyone give me some tips on how i would determine the shape of a ...
Chemistry - Explain the following observation in terms of the collision theory, ...
chem - For the gaseous equilibrium represented below, it is observed that ...
Chemistry Eq. Question - 3H2(g) + N2(g) reverse reaction arrow 2NH3(g) What ...
Chemistry - A chemical system within a sealed 1 L reaction vessel is described ...
For Further Reading
