PreCal
posted by Hannah on .
1)tan 5 degrees + tan 25 degrees / 1 tan 5 degrees tan 25 degrees =
sqrt 3 / 3 Am I correct?
2) Complete the identity
tan^2Q  3sinQtanQsecQ =
2tan^2Q Correct?

You are correct if your expression is
(tan5 + tan25)/(1  tan5tan25), which is not what you typed. 
yes, to your second part

(tan5 + tan25)/(1  tan5tan25)= tan (5+25) = tan 30 degrees = (sqrt 3)/3