Homework Help: Pre-Cal

Posted by Hannah on Wednesday, March 10, 2010 at 11:12pm.

1)tan 5 degrees + tan 25 degrees / 1 tan 5 degrees tan 25 degrees =

sqrt 3 / 3 Am I correct?

2) Complete the identity

tan^2Q - 3sinQtanQsecQ =

-2tan^2Q Correct?

Pre-Cal - Reiny, Thursday, March 11, 2010 at 12:05am
You are correct if your expression is
(tan5 + tan25)/(1 - tan5tan25), which is not what you typed.
Pre-Cal - Reiny, Thursday, March 11, 2010 at 12:07am
yes, to your second part
Pre-Cal - victor_hery, Friday, August 31, 2012 at 12:12am
(tan5 + tan25)/(1 - tan5tan25)= tan (5+25) = tan 30 degrees = (sqrt 3)/3

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