Posted by **ne** on Wednesday, March 10, 2010 at 11:08pm.

Find the orbital speed of an ice cube in the rings of Saturn, if the mass of Saturn is 5.67 × 1026 kg and the rings

have an average radius of 100,000 km.

- Physics -
**FredR**, Thursday, March 11, 2010 at 1:37am
Newton's law of gravitation:

F = G m1 m2 /r^2

let m2 = mass of ice cube and

s = G m1/r^2

so,

F = s m2

rearranging,

s = m2/F

let V = orbital speed

centripetal acceleration = V^2/r

For an object to remain in orbit s must equal the centripetal acceleration so,

s = V^2/r

- Physics -
**drwls**, Thursday, March 11, 2010 at 3:07am
Taking up where FredR left off,

V^2/r = G m/r^2

V^2 = G m/r

where m is the mass of Saturn.

G = 6.674*10^-11 N*m^2/kg^2

Solve for V

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