Posted by Tiffany on Wednesday, March 10, 2010 at 10:26pm.
Note iron(III) is written with capital Is and not lower case is.
2.5 g Fe/55.85 = xx moles Fe you need. (I have rounded here. You should go through and be a little more accurate. I will round down the line, too, so it will be necessary for you to through all of the calculations for a better answer.) 3 x moles Fe = moles oxalate ions = ?? moles oxalate.
xx moles Fe x (1 mol FeCl3/1 mole Fe) = moles FeCl3 and that times molar mass = grams FeCl3.
?? moles oxalate x (1 mol K2C2O4/1 mole C2O4) = moles K2C2O4 and that times molar mass K2C2O4 = g K2C3O4.
Check my thinking. Check my work.
I made a typo, next to last line, should be molar mass K2C2O4 = g K2C2O4 instead of what follows.
molar mass K2C2O4 = g K2C3O4.
Check my thinking. Check my work.
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