Posted by Stuck on .
"Colbalt-60 is a radioactive isotope used to treat cancers of the brain and other tissues. A gamma ray emitted by an atom of this isotope has an energy of 1.33 MeV (million electron volts; 1 eV = 1.602*10^-19 J). What is the frequency (in Hz) and wavelength (in m) of this gamma ray?"
I just want to make sure I got the frequency right.
Why didn't you post your work? That way we could tell you if you worked it right or not AND you would spend your time typing instead of us.
E =h*c/wavelength. Find wavelength.
c = freq * wavelength. Solve for freqency.
Oh right, sorry about that.
I used E=hf (f=E/h).
So I got E as 2.13*10^-13 J by...(1.33*10^6)(1.602*10^-19).
Using the formula, I got frequency as 3.22*10^20.
I think I've taken a different approach as what you have suggested.
Your method is a little shorter than mine. I arrive at the same answer for frequency. I assume you know the problem also asked for wavelength and that is
c = frequency x wavelength for which I obtained 9+ x 10^-13 meters. Thanks for showing your work.