the debate club needs $240.00 to attend a debate tournament. the club decides to sell iced tea and lemonade at baseball games. iced tea will be sold for $.50 per cup and lemonade will be sold for $.80 per cup. write the equation to find how many cups of each beverag must be sold to raise $240.00.
Let's assume the number of cups of iced tea to be sold as "x" and the number of cups of lemonade to be sold as "y".
Given that the iced tea is sold for $0.50 per cup and the lemonade is sold for $0.80 per cup, we can write the equation to represent the total amount of money raised:
0.50x + 0.80y = 240.00
This equation represents the total revenue from selling cups of iced tea and lemonade, which needs to equal $240.00 to cover the cost of attending the debate tournament.
To determine how many cups of each beverage must be sold to raise $240.00, we need to set up an equation.
Let's assume x represents the number of cups of iced tea sold and y represents the number of cups of lemonade sold.
The cost of each cup of iced tea is $0.50, so the total revenue from selling iced tea will be 0.50x dollars.
Similarly, the cost of each cup of lemonade is $0.80, so the total revenue from selling lemonade will be 0.80y dollars.
Since the debate club needs to raise $240.00, the equation to find the total revenue is: 0.50x + 0.80y = 240.00.
Therefore, the equation is 0.50x + 0.80y = 240.00.
Let x = cups of lemonade and y = cups of tea.
.50y + .80x = 240
This equation needs more information to be solved. As x increases, y will decrease.