Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80
Miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at
1:20 am A.M. If train B passes the same station at 1:35 A.M., at what time will train B catch up to
Train A?
can someone please me understand how to solve this problem?
Thanks.
College?
When Train B passes, Train A is 20 miles ahead. (80 mph x 1/4 hour)
The gap between the trains then closes at a rate of 88-80 = 8 mph. B catches up in 20/8 = 2.5 hours.
Add 2 hours and 30 minutes to 1:35 AM