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October 1, 2014

October 1, 2014

Posted by **Sandy** on Wednesday, March 10, 2010 at 5:05pm.

- trig -
**FredR**, Wednesday, March 10, 2010 at 6:14pm9cos^2(t)+3cos(t)=0

subtract 3cos(t) from both sides

9cos^2(t)=-3cos(t)

divide both sides by 3cos(t)

3cos(t)=-1

cos(t)=-1/3

t=arccos(-1/3)

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