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December 20, 2014

December 20, 2014

Posted by **M.A.** on Wednesday, March 10, 2010 at 1:27pm.

Choose one:

5

10

20

40

----------------------

My reasoning:

There are 5 students. I will name them student A, B, C, D, and E.

First grouping: AB

CDE

BC

DEA

etc. = 5 ways to combine students.

Second grouping: AC

BDE

BD

EAC

etc. = 5 ways to combine students.

Third grouping: CE

ABD

etc. = 5 ways to combine students.

Fourth grouping: AD

etc. = 5 ways

Fifth grouping: AE

etc. = 5 ways

5 groupings with 5 ways to combine students = 20 ways to group.

So, is the answer "20" or am I to assume

that they can be further grouped depending upon the unexplained tasks of

the class project?

- math logic -
**Reiny**, Wednesday, March 10, 2010 at 1:30pmUsing combinations,

number of ways = C(5,3)xC(2,2) = 20x1 = 20

You are right.

- math logic -
**M.A.**, Wednesday, March 10, 2010 at 1:36pmThank you!

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