Posted by **Kelsey** on Wednesday, March 10, 2010 at 1:25pm.

Tarzan swings on a 27.0 m long vine initially inclined at an angle of 33.0° with the vertical.

(a) What is his speed at the bottom of the swing if he starts from rest?(b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s?

- Physics -
**bobpursley**, Wednesday, March 10, 2010 at 2:15pm
draw the sketch. How high is he initially?

intialPE=finalKE

b) initialPE+ intialKE= finalKE

- Physics -
**Kelsey**, Wednesday, March 10, 2010 at 6:18pm
I drew the sketch, the problem does not tell me how high he is initially, I can find the equation vfinal = the square root of (2gh) but I don't know what h is.

## Answer this Question

## Related Questions

- physics - Tarzan swings on a 27.0 m long vine initially inclined at an angle of ...
- physics - Tarzan swings on a 23.2 m long vine initially inclined at an angle of ...
- physics - Tarzan swings on a 28.0 m long vine initially inclined at an angle of ...
- physics... - Tarzan swings on a 26.2 m long vine initially inclined at an angle ...
- physics - Tarzan swings on a 34.0-m-long vine initially inclined at an angle of ...
- Physics - Tarzan swings on a 27.0 m long vine initially inclined at an angle of ...
- College Physics - Tarzan spies a 35kg chimpanzee in severe danger, so he swings ...
- physics - Tarzan is often portrayed as swinging through the jungle from vine to ...
- NEED HELP PHYSICS!!! - Tarzan (m = 78.4 kg) tries to cross a river by swinging ...
- physics - Tarzan (m = 75 kg) tries to cross a river by swinging from a 10.0 m ...