Posted by Kelsey on Wednesday, March 10, 2010 at 1:25pm.
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 33.0° with the vertical.
(a) What is his speed at the bottom of the swing if he starts from rest?(b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s?

Physics  bobpursley, Wednesday, March 10, 2010 at 2:15pm
draw the sketch. How high is he initially?
intialPE=finalKE
b) initialPE+ intialKE= finalKE

Physics  Kelsey, Wednesday, March 10, 2010 at 6:18pm
I drew the sketch, the problem does not tell me how high he is initially, I can find the equation vfinal = the square root of (2gh) but I don't know what h is.

Physics  Kathryn, Thursday, December 10, 2015 at 4:54am
I know this is about 5 years too late, but h would be the length of the vine (21 m)

Physics  Anonymous, Sunday, December 11, 2016 at 10:56pm
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 24° from the vertical.
What is his speed at the bottom of the swing if he starts from rest?
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