Posted by Kelsey on .
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 33.0° with the vertical.
(a) What is his speed at the bottom of the swing if he starts from rest?(b) What is his speed at the bottom of the swing if he pushes off with a speed of 3.00 m/s?

Physics 
bobpursley,
draw the sketch. How high is he initially?
intialPE=finalKE
b) initialPE+ intialKE= finalKE 
Physics 
Kelsey,
I drew the sketch, the problem does not tell me how high he is initially, I can find the equation vfinal = the square root of (2gh) but I don't know what h is.

Physics 
Kathryn,
I know this is about 5 years too late, but h would be the length of the vine (21 m)

Physics 
Anonymous,
Tarzan swings on a 27.0 m long vine initially inclined at an angle of 24° from the vertical.
What is his speed at the bottom of the swing if he starts from rest?