Wednesday

March 4, 2015

March 4, 2015

Posted by **Sally** on Wednesday, March 10, 2010 at 1:18pm.

- math -
**FredR**, Wednesday, March 10, 2010 at 5:31pm16-15.2 = 0.8

0.8/0.03 = n = 26 standard deviations

so,

erf(n/sqrt(2)) = approximately 1

so,

50% of the data would be between 15.2 and 16.

- math -
**PsyDAG**, Thursday, March 11, 2010 at 11:23amAre you sure there are no typos in your data?

If so, find the Z scores for both scores.

Z = (score-mean)/Standard deviation

In the back of your stat text, find the Z scores in a table labeled something like "areas under the normal distribution." Find the proportion between the two scores and convert to a percentage.

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