Posted by **Anonymous** on Wednesday, March 10, 2010 at 11:29am.

A boy pulls a sled of mass 5.0 kg with a rope that makes an 60.0° angle with respect to the

horizontal surface of a frozen pond. The boy pulls on the rope with a force of 10.0 N; and the

sled moves with constant velocity. What is the coefficient of friction between the sled and the

ice?

- physics -
**drwls**, Wednesday, March 10, 2010 at 12:32pm
Constant velocity means that the forces add up to zero.

Do a force balance in the direction of motion. It says:

10.0 cos 60 = friction force = (M g - 10.0 sin 60)*Uk

Solve for Uk, the coefficient of (kinetic) friction.

The reason for the -10.0 sin 60 term is that the upward pull on the rope reduces the normal force of the sled onto the ice. That term gets subtracted from the sled's weight.

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