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October 20, 2014

October 20, 2014

Posted by **GGIFT** on Wednesday, March 10, 2010 at 7:39am.

x^2+3x over x^2+2x-3 by x over x+1.. i know to do the recip. of x over x+1 and get the foll.

x^2 + 3x over x^2 + 2x -3 times x+1 over x... now

(x^2+3x)(x+1) over

(x^2+2x-3)(x)

now

x(x+2)(x+1)

x(x+2)(x-1)

the x+2 over x+2 = 1

so wouldn't the value be 1?

- ALGEBRA -
**Reiny**, Wednesday, March 10, 2010 at 8:16amx^2+3x over x^2+2x-3 by x over x+1

= (x^2+3x)/(x^2+2x-3)*(x)/(x+1)

= x(x+3)/[(x+3)(x-1)*x?(x+1)

= x/(x-1)*x/(x+1)

= x^2/(x^1 - 1)

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