A buffered solution is made by adding 50.0 g NH4Cl to 1.00 L of a 0.70 M solution of NH3. Calculate the pH of the final solution. (Assume no volume change.)

Use the Henderson-Hasselbalch equation.

Moles

To calculate the pH of the final solution, we need to consider the reaction between NH4Cl and NH3.

First, let's write down the balanced equation:

NH4Cl + NH3 -> NH4+ + Cl-

NH4+ is the conjugate acid of NH3, and Cl- is a spectator ion. We can ignore Cl- in the calculation.

Now, let's analyze the solution composition:

NH3 is the weak base and NH4+ is a weak acid. When they are present together in a solution, they form a buffer system that resists changes in pH.

To determine the pH, we need to calculate the concentration of NH4+ in the solution. We know that we added 50.0 g of NH4Cl, so we need to convert this mass to moles:

molar mass of NH4Cl = 14.01 g/mol (atomic mass of N) + 4 * 1.01 g/mol (atomic mass of H) + 35.45 g/mol (atomic mass of Cl) = 53.46 g/mol

moles of NH4Cl = mass / molar mass = 50.0 g / 53.46 g/mol

Next, we need to determine the concentration of NH4+ in the solution. Since we added 50.0 g of NH4Cl to 1.00 L of solution, the concentration of NH4+ can be calculated using the formula:

concentration = moles / volume

For NH4+, the moles are the same as NH4Cl, so the concentration of NH4+ is:

concentration of NH4+ = moles of NH4+ / volume of solution

Now, let's calculate the concentration of NH4+:

volume of solution = 1.00 L

concentration of NH4+ = moles of NH4+ / volume of solution

Next, we calculate the moles of NH4+:

moles of NH4+ = moles of NH4Cl = 50.0 g / 53.46 g/mol

Finally, we calculate the concentration of NH4+:

concentration of NH4+ = (50.0 g / 53.46 g/mol) / 1.00 L

Now that we have the concentration of NH4+, we can use the Henderson-Hasselbalch equation to calculate the pH:

pH = pKa + log10(concentration of NH3 / concentration of NH4+)

The pKa value for NH3/NH4+ pair is typically given as 9.25.

Substituting the values into the Henderson-Hasselbalch equation, we get:

pH = 9.25 + log10(concentration of NH3 / concentration of NH4+)

Finally, calculate the pH by substituting the values into the equation and solving:

pH = 9.25 + log10(0.70 / concentration of NH4+)

By calculating the concentration of NH4+ and plugging it into the equation, you can determine the pH of the final solution.