Posted by Stuck on Tuesday, March 9, 2010 at 10:25pm.
draw a radius from the centre to a vertex of the rectangle
Let the base of the rectangle be 2x, making the triangle base x, and let the height of the rectangle by y
Area of rectangle = 2xy
but x^2 + y^2 = 4
y = √(4 - x^2) or (4-x^2)^(1/2)
A = 2x(4-x^2)^(1/2)
take the derivative using the product rule,
set it equal to zero and solve for x
Thank you! Never occurred to me to position the radius like that.
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