Posted by Anonymous on Tuesday, March 9, 2010 at 7:41pm.
H3PO4 ==> H^+ + H2PO4^-
K1 = (H^+)(H2PO4^-)/(H3PO4)
You are given H3PO4 and pH. For all practical purposes, although H3PO4 has k1, k2, and k3, the first ionization of k1 is so large in comparison with the others that you may consider this a monoprotic acid, at least for the purposes of this problem. Use pH to find (H^+), set up and ICE chart, substitute into Ka expression and solve for Ka.
what is the molarity of an aqueous solution containing 40 g of glucose (c6h12o6) in 1.5 L in solution
molarity = moles/L soln.
moles = 40/molar mass.
L soln = 1.5 L
Plug and chug.
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