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December 20, 2014

December 20, 2014

Posted by **Tom** on Tuesday, March 9, 2010 at 7:21pm.

2(cos(4pi/3) + isin(4pi/3))

I don't understand where to go from here.

- pre-calculus -
**Reiny**, Tuesday, March 9, 2010 at 7:40pmcos(4pi/3) = - 1/2

sin(4pi/3) = - √3/2

so

2(cos(4pi/3) + isin(4pi/3)) = -1/2 - (√3/2)i

here is a nice page for this topic

http://www.allaboutcircuits.com/vol_2/chpt_2/5.html

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