true or false- correct/explain those that is false
Benzene is generally more reactive than alkanes and less reactive than alkenes because of the bonding in its aliphatic ring
The polymer produced from polymerization of H2NCH2COOH is......?
Write out the formula/equation
The preparation of a 2-pentanone from an alcohol
I generally agree with #1 as true; however, "bonding in its aliphatic ring" is completely out of touch so I would answer false. Bonding in benzene definitely is NOT aliphatic in nature.
#2 and #3 aren't true/false questions. What do you think about them?
ohh sorry i meant the first one is true and false.
for #2 and #3 i am stuck
For polymerization of glycine, look in your notes or text for its use in the formation of proteins.
Look in your notes in your text for the preparation of alcohols. One common method is to hydrate an alkene. One can start with CH3CH2CH2CH=CH2 and hydrate it.
False: Benzene is actually less reactive than both alkanes and alkenes due to its aromatic ring structure. The stability of the delocalized pi electrons in the benzene ring restricts its reactivity compared to alkanes and alkenes, which can undergo addition reactions more readily.
To determine the polymer produced from the polymerization of H2NCH2COOH, we need to understand the structure and reactivity of the starting monomer.
H2NCH2COOH is the molecular formula for the amino acid called glycine. Polymerization of glycine involves the reaction of the amino (NH2) group with the carboxylic acid (COOH) group, resulting in the formation of a peptide bond.
When glycine undergoes polymerization, multiple glycine molecules join together through peptide linkages, forming a chain-like structure. This process is known as peptide bond formation or condensation polymerization.
The resulting polymer is a polypeptide, which consists of a sequence of amino acids connected through peptide bonds. Polypeptides are an essential component of proteins in living organisms.
Therefore, the polymer produced from the polymerization of H2NCH2COOH (glycine) is a polypeptide.
To prepare 2-pentanone from an alcohol, we need to follow a specific organic synthesis pathway. The most common method involves the oxidation of 2-pentanol (the alcohol) to form 2-pentanone (the ketone).
The balanced equation for this oxidation reaction is as follows:
2-pentanol + [O] → 2-pentanone + H2O
In this equation, the [O] represents an oxidizing agent, commonly an oxidizing agent like potassium dichromate (K2Cr2O7) or chromic acid (H2CrO4).
To carry out this synthesis, one would typically react 2-pentanol with the chosen oxidizing agent under appropriate reaction conditions, such as reflux or using a catalyst. The specific reagents and conditions may vary depending on the synthetic procedure being followed.
It's important to note that the reaction conditions and choice of reagents should be selected based on the desired yield and reaction efficiency, as well as safety considerations. It is recommended to consult a reliable organic chemistry source or a lab manual for detailed instructions on the preparation of 2-pentanone from an alcohol.